The Town of Hickory Creek had a population of 4,600 as of July 1, 2018.
The primary coordinate point for Hickory Creek is located at latitude 33.1111 and longitude -97.0328 in Denton County. The formal boundaries for the Town of Hickory Creek (see map below) encompass a land area of 4.54 sq. miles and a water area of 0.09 sq. miles. Denton County is in the Central time zone (GMT -6). The elevation is 577 feet.
The Town of Hickory Creek (GNIS ID: 2412749) has a C1 Census Class Code which indicates an active incorporated place that does not serve as a county subdivision equivalent. It also has a Functional Status Code of "A" which identifies an active government providing primary general-purpose functions.
Texas is one of 20 states where Census County Divisions (CCDs) are used for statistical tracking of subdivisions within each county. The Town of Hickory Creek is located within Lewisville-Flower Mound Division of Denton County.
|Population in Households||4,600|
|Population in Familes||4,089|
|Population in Group Qrtrs||0|
|Median Household Income||$110,633|
|Average Household Income||$135,086|
|Per Capita Income||$46,898|
|Total Housing Units||1,658 (100%)|
|Owner Occupied HU||1,382 (83.4%)|
|Renter Occupied HU||251 (15.1%)|
|Vacant Housing Units||25 ( 1.5%)|
|Median Home Value||$286,890|
|Average Home Value||$308,321|
|Average Household Size||2.82|
|Average Family Size||3|
GROWTH RATE / YEAR
|Median Household Income||0.69%|
|Per Capita Income||1.47%|
The table below compares Hickory Creek to the other 1,749 incorporated cities, towns and CDPs in Texas by rank and percentile using July 1, 2018 data. The location Ranked # 1 has the highest value. A location that ranks higher than 75% of its peers would be in the 75th percentile of the peer group.
|Total Population||# 434||75th|
|Population Density||# 715||59th|
|Diversity Index||# 1184||32nd|
|Median Household Income||# 74||96th|
|Per Capita Income||# 102||94th|
Additional comparisons and rankings can be made with a VERY EASY TO USE Texas Census Data Comparison Tool.